用Jersey构建RESTful服务1--HelloWorld
时间:2014-03-18 04:33:31
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一、环境
1、Eclipse Juno R2
2. Tomcat 7
3. Jersey 2.7 下载地址( https://jersey.java.net/download.html)
二、流程
1.Eclipse 中创建一个 Dynamic Web Project ,本例为“RestDemo”
5.修改web.xml,添加基于Servlet-的部署
6.项目部署到tomcat,运行
7.浏览器输入要访问的uri地址
http://localhost:8089/RestDemo/rest/hello
http://localhost:8089/RestDemo/rest/hello/Way你好吗
输出Hello Way你好吗

参考:https://jersey.java.net/documentation/latest/user-guide.html
1、Eclipse Juno R2
2. Tomcat 7
3. Jersey 2.7 下载地址( https://jersey.java.net/download.html)
二、流程
1.Eclipse 中创建一个 Dynamic Web Project ,本例为“RestDemo”
2.按个各人习惯建好包,本例为“com.waylau.rest.resources”
将api、ext、lib文件夹下的jar包都放到项目的lib下;
项目引入jar包
package com.waylau.rest.resources; import javax.ws.rs.GET; import javax.ws.rs.Path; import javax.ws.rs.Produces; import javax.ws.rs.PathParam; import javax.ws.rs.core.MediaType; @Path("/hello") public class HelloResource { @GET @Produces(MediaType.TEXT_PLAIN) public String sayHello() { return "Hello World!" ; } @GET @Path("/{param}") @Produces("text/plain;charset=UTF-8") public String sayHelloToUTF8(@PathParam("param") String username) { return "Hello " + username; } }
5.修改web.xml,添加基于Servlet-的部署
<servlet> <servlet-name>Way REST Service</servlet-name> <servlet-class>org.glassfish.jersey.servlet.ServletContainer</servlet-class> <init-param> <param-name>jersey.config.server.provider.packages</param-name> <param-value>com.waylau.rest.resources</param-value> </init-param> <load-on-startup>1</load-on-startup> </servlet> <servlet-mapping> <servlet-name>Way REST Service</servlet-name> <url-pattern>/rest/*</url-pattern> </servlet-mapping>
6.项目部署到tomcat,运行
7.浏览器输入要访问的uri地址
http://localhost:8089/RestDemo/rest/hello
输出Hello World!
http://localhost:8089/RestDemo/rest/hello/Way你好吗
输出Hello Way你好吗

参考:https://jersey.java.net/documentation/latest/user-guide.html
用Jersey构建RESTful服务1--HelloWorld,布布扣,bubuko.com
原文:http://blog.csdn.net/kkkloveyou/article/details/21391033
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