MySQL 获取连续范围

时间:2015-04-21 16:03:48   收藏:0   阅读:329

1、原始数据
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2、把running_number转成数据,并加上一列有序数字

SELECT d.running_number+0 running_number,@a:=@a+1 rn FROM device_data d,(SELECT @a:=0) a 
where d.device_id=13 order by d.running_number;

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3、running_number与有序数据的差,差(diff)相同的的running_number说明是连续的

SELECT running_number,rn,running_number-rn diff
FROM 
(SELECT d.running_number+0 running_number,@a:=@a+1 rn 
FROM device_data d,(SELECT @a:=0) a where d.device_id=13) b;

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4、根据差来分组,并获得相关差的最小及最大running_number,就形成了连续范围

select min(c.running_number) min,max(c.running_number) max
from
(SELECT running_number,rn,running_number-rn diff
  FROM 
(SELECT d.running_number+0 running_number,@a:=@a+1 rn 
FROM device_data d,(SELECT @a:=0) a where d.device_id=13)
 b)c group by diff;

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5、参考《MySQL技术内幕:SQL编程》 2.6.2连续范围问题

原文:http://blog.csdn.net/jrainbow/article/details/45171533

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