JsonConvert After parsing a value an unexpected character was encountered

JsonConvert.DeserializeObject<T>(data);

报错：After parsing a value an unexpected character was encountered

错误原因是没有进行json转义

错误用法：return Json<T>(t); 输出未转义json

正确用法：return Json(JsonConvert.SerializeObject(t)); 输出转义后json

原文：https://www.cnblogs.com/SolutionX/p/14645012.html