shell 判断字符串是否包含另一个字符串
时间:2020-12-16 12:10:01
收藏:0
阅读:722
1.使用grep
s1="helloworld"
s2="ello"
result=$(echo $s1 | grep "${s2}")
if [[ "$result" != "" ]]
then
echo "$s1 include $s2"
else
echo "$1 not include $s2"
fi
2. 使用操作符~
fileName=/home/sss/data/cl
if [[ $fileName =~cl ]]
then
echo "$fileName include cl"
else
echo "not include"
fi
3. 使用通配符*
A="helloworld"
B="low"
if [[ $A == *$B* ]]
then
echo "包含"
else
echo "不包含"
fi
原文:https://www.cnblogs.com/cchilei/p/14142776.html
评论(0)