列表的排序和统计。
时间:2020-07-13 11:51:10
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l1 = [1,2,3,4,2,4,2,6,8] l2 = list() # 列表排序 i = 0 for i in l1 : if i not in l2 : l2.append(i) print(l2) #count 统计次数 for i in l1: if i not in l2: # l2.append(i) l2.append(str(1)) else: l2[l2.index(i) + 1] = str(int(l2[l2.index(i) + 1])+1) print(l2) for i in range(0,len(l2),2): print(l2[i],l2[i+1],sep=‘----‘)
原文:https://www.cnblogs.com/kaiyaoweixiao/p/13292214.html
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