egret简单的椭圆或圆周运动

public do(){

egret.Tween.get(t, { loop: true }).to({ fa: 180 }, 2000);

}

public get fa(): number {
return -180;
}

public set fa(s) {
let chang = 50;
let duan = 20;//长短一样时就是圆周运动
let xx = chang;
let yy = 0;

this.x = xx + Math.cos(s * Math.PI / 180) * chang;
this.y = yy + Math.sin(s * Math.PI / 180) * duan;
}

原文：https://www.cnblogs.com/jiajunjie/p/12486650.html