剑指OFFER----面试题24. 反转链表

时间:2020-02-24 18:08:42   收藏:0   阅读:82

链接:https://leetcode-cn.com/problems/fan-zhuan-lian-biao-lcof/

 

代码:

/**
 * Definition for singly-linked list.
 * struct ListNode {
 *     int val;
 *     ListNode *next;
 *     ListNode(int x) : val(x), next(NULL) {}
 * };
 */
class Solution {
public:
    ListNode* reverseList(ListNode* head) {
        ListNode* pre = nullptr;
        auto cur = head;
        while (cur) {
            auto tmp = cur->next;
            cur->next = pre;
            pre = cur;
            cur = tmp;
        }
        return pre;
    }
};

 

原文:https://www.cnblogs.com/clown9804/p/12357904.html

评论(0
© 2014 bubuko.com 版权所有 - 联系我们:wmxa8@hotmail.com
打开技术之扣,分享程序人生!