Plus One

时间:2014-08-31 23:05:42   收藏:0   阅读:563

问题描述

Given a non-negative number represented as an array of digits, plus one to the number.

The digits are stored such that the most significant digit is at the head of the list.

解决方案

public class Solution {
	public int[] plusOne(int[] digits) {
		int length = digits.length;
		boolean addOneDigit = true;
		for( int digit : digits ) {
			if( digit != 9 ) {
				addOneDigit = false;
				break;
			}
		}
		int[] result = addOneDigit ? new int[length + 1] : new int[length];

		if( addOneDigit ) {
			result[0] = 1;
			for( int i = 1; i < length; ++i ) {
				result[i] = 0;
			}
			return result;
		}

		int add = 1;
		for( int i = length - 1; i >= 0; --i ) {
			result[i] = digits[i] + add;
			if( add == 1 ){
				add = 0;
			}
			if( result[i] == 10 ) {
				result[i] = 0;
				add = 1;
			}
		}
		return result;
	}
}


原文:http://blog.csdn.net/senlinzm/article/details/38963785

评论(0
© 2014 bubuko.com 版权所有 - 联系我们:wmxa8@hotmail.com
打开技术之扣,分享程序人生!