postgresql 两行数据时间之差

时间：2020-01-20 21:54:01 收藏：0 阅读：136

//获取两行之间的时间差，并转换成分钟

1 select *,extract(epoch from((aaa."ar"::timestamp) - (bbb."br"::timestamp)))/60 as counterDiffer from 
2 (select row_number() OVER (ORDER BY "ID") as aa,"ReceiveTime" as ar from public."YourTableName" where "searchID" = ‘123456‘) as aaa,
3 (select row_number() OVER (ORDER BY "ID") as bb,"ReceiveTime" as br from public."YourTableName" where "searchID" = ‘123456‘) as bbb 4 where aa -1 =bb order by ar

原文：https://www.cnblogs.com/indexlang/p/12219520.html