LeetCode Solutions : N-Queens II

时间:2014-08-25 19:22:11   收藏:0   阅读:261

Follow up for N-Queens problem.

Now, instead outputting board configurations, return the total number of distinct solutions.

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Java Solutions( Refer to blog  http://blog.csdn.net/mbh_1991/article/details/23869459 and  http://blog.csdn.net/u011095253/article/details/9158473   ):

public class Solution {
	int count;
    public int totalNQueens(int n) {
        count=0;
		int[] location=new int[n];
		dfs(location,0,n);
		return count;
    }
	private void dfs(int[] location,int cur,int n){
		if(cur==n)
			count++;
		else{
			for(int i=0;i<n;i++){
				location[cur]=i;
				if(isValid(location,cur))
					dfs(location,cur+1,n);
			}
		}
	}
	private boolean isValid(int[] location,int cur){
		for(int i=0;i<cur;i++){
			if(location[i]==location[cur]||Math.abs(location[i]-location[cur])==cur-i)
				return false;
		}
		return true;
	}
}

原文:http://blog.csdn.net/lviiii/article/details/38823873

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