leetcode1271

时间:2019-12-01 10:17:21   收藏:0   阅读:69
 1 class Solution:
 2     def toHexspeak(self, num: str) -> str:
 3         dic = {a:A,b:B,c:C,d:D,e:E,f:F,1:I,0:O}
 4         dn_10 = int(num)
 5         dn_16 = hex(dn_10)#10进制转16进制
 6         str_16 = str(dn_16)[2:]#去掉前缀 0x
 7         r = ‘‘
 8         for i in range(len(str_16)):
 9             if str_16[i] in dic:
10                 r += dic[str_16[i]]
11             else:
12                 return ERROR
13         return r

 

原文:https://www.cnblogs.com/asenyang/p/11965104.html

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