es6方法过滤掉两个数组中对象id值相等的项

let arr1=[{id:1,name:‘张三‘},{id:2,name:‘李四‘}]
let arr2=[{id:1,name:‘张三‘},{id:3,name:‘王五‘},{id:44,name:‘王柳‘},{id:45,name:‘王琦‘},]

let add=arr2.filter(item=>!arr1.some(ele=>ele.id===item.id))
  console.log(add)

const arr1 = [{ id: 1, name: ‘网‘ }, { id: 2, name: ‘二位‘ }];
const arr2 = [{ id: 1, name: ‘老二‘ }, { id: 3, name: ‘老三‘ }];
// 获取到arr1的所有id集合
let arr1Ids = arr1.map(item => item.id);
// 过滤arr2中不包含arr1相同的id数组。
const result = arr2.filter(item => !arr1Ids.includes(item.id));
console.log(result); // [{id: 3, name: "老三"}];

原文：https://www.cnblogs.com/wgy0528/p/10875969.html