MYSQL 查询指定范围内的经纬度
时间:2018-08-24 12:57:16
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select * from `location` where ( acos( sin(([#latitude#]*3.1415)/180) * sin((latitude*3.1415)/180) + cos(([#latitude#]*3.1415)/180) * cos((latitude*3.1415)/180) * cos(([#longitude#]*3.1415)/180 - (longitude*3.1415)/180) )*6370.996 )<=1;
原文:https://www.cnblogs.com/banywl/p/9528868.html
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