spring jpa exists

时间：2018-04-08 13:56:16 收藏：0 阅读：736

Subquery<A> subquery = criteriaQuery.subquery(A.class);
Root<A> root1 = subquery.from(A.class);

subquery = subquery.select(root1.get("attrx"));
subquery = subquery.where(criteriaBuilder.and(
        criteriaBuilder.equal(root1.get("attr1"), root.get("attr11")),
        criteriaBuilder.equal(root1.get("attr2"), "value")
));

criteriaBuilder.exists(subquery)

原文：https://www.cnblogs.com/white-knight/p/8744431.html