Oracle 切割字符查询

时间:2018-02-15 14:14:32   收藏:0   阅读:268
Oracle 切割字符查询

select *
  from view_psbaseinfo
 where DECODE(‘410782001125,411100000043‘,
              ‘‘,
              NULL,
              ‘410782001125,411100000043‘) IS NULL
    or PSCODE in
       (SELECT REGEXP_SUBSTR(‘410782001125,411100000043‘, ‘[^,]+‘, 1, LEVEL) AS PSCODE
          FROM DUAL
        CONNECT BY LEVEL <=
                   LENGTH(‘410782001125,411100000043‘) + 1 -
                   LENGTH(REPLACE(‘410782001125,411100000043‘, ‘,‘, ‘‘)));

原文:https://www.cnblogs.com/zhchoutai/p/8449473.html

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