SQL Server 取前一天的0点和23点59分59秒

DECLARE @startDate1 DATE;
DECLARE @startDate DATETIME;
SET @startDate1=GETDATE();SELECT @startDate=DATEADD(DAY,-1,@startDate1); 
DECLARE @endDate DATETIME ;SET @endDate=DATEADD(second,-1,CONVERT(DATETIME,@startDate1)); 
SELECT @startDate startDate,@endDate endDate;

startDate               endDate
----------------------- -----------------------
2014-05-19 00:00:00.000 2014-05-19 23:59:59.000

原文：http://www.cnblogs.com/amylis_chen/p/7545042.html