ORACLE 按逗号拆分字符串为多行

时间:2017-05-10 12:40:41   收藏:0   阅读:1299
with t as
 (select 1,2,3,10,11,12 a from dual)
select substr(a,
              decode(level - 1, 0, 0, instr(a, ,, 1, level - 1)) + 1,
              (decode(level,
                      regexp_count(a, ,) + 1,
                      length(a) + 1,
                      instr(a, ,, 1, level))) -
              (decode(level - 1, 0, 0, instr(a, ,, 1, level - 1)) + 1))
  from t
connect by level <= regexp_count(a, ,) + 1;

 

原文:http://www.cnblogs.com/wolil/p/6834933.html

评论(0
© 2014 bubuko.com 版权所有 - 联系我们:wmxa8@hotmail.com
打开技术之扣,分享程序人生!