/** * Definition for binary tree * struct TreeNode { * int val; * TreeNode *left; * TreeNode *right; * TreeNode(int x) : val(x), left(NULL), right(NULL) {} * }; */ class Soluti
时间:2017-03-23 20:42:54
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/**
* Definition for binary tree
* struct TreeNode {
* int val;
* TreeNode *left;
* TreeNode *right;
* TreeNode(int x) : val(x), left(NULL), right(NULL) {}
* };
*/
class Solution {
public:
TreeNode* reConstructBinaryTree(vector<int> pre,vector<int> vin) {
if(pre.size()==0||vin.size()==0)
return NULL;
TreeNode* p=new TreeNode(pre[0]);
int i;
for(i=0;i<vin.size();i++)
if(pre[0]==vin[i])
break;
vector<int> left_pre,left_vin,right_pre,right_vin;
for(int j=0;j<i;j++)
{left_pre.push_back(pre[j+1]);
left_vin.push_back(vin[j]);}
for(int j=i+1;j<pre.size();j++)
{right_pre.push_back(pre[j]);
right_vin.push_back(vin[j]);}
p->left=reConstructBinaryTree(left_pre,left_vin);
p->right=reConstructBinaryTree(right_pre,right_vin);
return p;
}
};
原文:http://www.cnblogs.com/cxy931980808/p/6606707.html
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