一种字段串的拆分

时间:2017-01-04 22:00:06   收藏:0   阅读:271
CREATE FUNCTION fn_getstring
(
@key VARCHAR(MAX) ,
@string VARCHAR(MAX) ,
@star INT ,
@step INT
)
RETURNS VARCHAR(MAX)
BEGIN
DECLARE @result VARCHAR(MAX)
SET @result = ‘‘

SELECT @result = @result + SUBSTRING(words, n,
CHARINDEX(,, words + ,,
n) - n) + ,
FROM ( SELECT @string words
) array
JOIN dbo.Nums ON n <= LEN(words)
AND SUBSTRING(@key + words, n, 1) = @key
WHERE ( n - LEN(REPLACE(LEFT(words, n), @key, ‘‘)) + 1 ) BETWEEN @star
AND
@end

RETURN SUBSTRING (@result,1, LEN(@result)-1)
END

 

原文:http://www.cnblogs.com/BinBinGo/p/6250251.html

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