Lintcode 469. 等价二叉树

时间:2017-01-01 23:39:50   收藏:0   阅读:298

技术分享

-----------------------------------------------

 

AC代码:

/**
 * Definition of TreeNode:
 * public class TreeNode {
 *     public int val;
 *     public TreeNode left, right;
 *     public TreeNode(int val) {
 *         this.val = val;
 *         this.left = this.right = null;
 *     }
 * }
 */
public class Solution {
    /**
     * @param a, b, the root of binary trees.
     * @return true if they are identical, or false.
     */
    public boolean isIdentical(TreeNode a, TreeNode b) {
        if(a==null && b==null) return true;
        else if(a==null || b==null) return false;
        else if(a.val!=b.val) return false;
        return isIdentical(a.left,b.left) && isIdentical(a.right,b.right);
    }
}

 

 

题目来源: http://www.lintcode.com/zh-cn/problem/identical-binary-tree/

原文:http://www.cnblogs.com/cc11001100/p/6241802.html

评论(0
© 2014 bubuko.com 版权所有 - 联系我们:wmxa8@hotmail.com
打开技术之扣,分享程序人生!