九度OJ 1068 球半径和数量 (模拟)

#include<stdio.h>
#include<math.h>
double X0,Y0,Z0,X1,Y1,Z1;
void solve(){
    double pi=acos(-1);//arccos在c里头就是acos
    double r;
    double v;
    r=sqrt(pow(fabs(X1-X0),2)+pow(fabs(Y1-Y0),2)+pow(fabs(Z1-Z0),2));
    v=4.0/3*pi*pow(r,3);
    printf("%.3lf %.3lf\n",r,v);
}
int main(int argc, char *argv[])
{
    //freopen("1068.in", "r", stdin);
    while(~scanf("%lf %lf %lf %lf %lf %lf",&X0,&Y0,&Z0,&X1,&Y1,&Z1))
    {
        solve();
    }
    return 0;
}
 
/**************************************************************
    Problem: 1068
    User: kirchhoff
    Language: C
    Result: Accepted
    Time:10 ms
    Memory:1004 kb
****************************************************************/