C++ 指针的偏移 The offset of a pointer in C++

时间：2014-04-02 05:03:39 收藏：0 阅读：590

A problem from my friend, what‘s the result of the following code:

class str{
public:
  int x;
  char s[0];
};

class foo{
public:
  str * p;
};
int main() {
  foo f = {0};
  str* p1 = NULL;
  if (f.p->s){
    printf("%d\n", f.p->s);
  }
  return 0;
}

This sentence sets p to NULL:

  foo f = {0};

f.p is a pointer of str, so f.p is an offset. I.e., f.p->s = base address + 4

So the result is 4

C++ 指针的偏移 The offset of a pointer in C++,布布扣,bubuko.com

原文：http://blog.csdn.net/taoqick/article/details/22760129