C#后台解析XML字符串并获取节点值
时间:2015-08-25 18:34:19
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XmlDocument xDoc = new XmlDocument();
xDoc.LoadXml(System.Web.HttpUtility.UrlDecode(mCuTable.DATASOURCE));
sDataSourceName = xDoc.SelectNodes("datasource/dataset")[0].Attributes["id"].Value;
sDatasetType = xDoc.SelectNodes("datasource/dataset")[0].Attributes["type"].Value;
xDoc.LoadXml(System.Web.HttpUtility.UrlDecode(mCuTable.DATASOURCE));
sDataSourceName = xDoc.SelectNodes("datasource/dataset")[0].Attributes["id"].Value;
sDatasetType = xDoc.SelectNodes("datasource/dataset")[0].Attributes["type"].Value;
原文:http://www.cnblogs.com/zecVip/p/4757929.html
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